ispunct() - C函式

C庫函式 int ispunct(int c) 檢查傳遞的字元是否是標點符號品格的標點符號是任何圖形字元（如isgraph）這是不是字母，數位（isalnum），。

宣告

以下是ispunct（）函式的宣告。

int ispunct(int c);

引數

c -- 這是要檢查的字元。

返回值

這個函式如果c是一個標點符號一樣返回一個非零值（true），否則返回零（false）

例子

下面的例子顯示ispunct（）函式的用法。

#include <stdio.h>
#include <ctype.h>

int main()
{
   int var1 = 't';
   int var2 = '1';
   int var3 = '/';
   int var4 = ' ';

   if( ispunct(var1) )
   {
       printf("var1 = |%c| is a punctuation character
", var1 );
   }
   else
   {
       printf("var1 = |%c| is not a punctuation character
", var1 );
   }
   if( ispunct(var2) )
   {
       printf("var2 = |%c| is a punctuation character
", var2 );
   }
   else
   {
       printf("var2 = |%c| is not a punctuation character
", var2 );
   }
   if( ispunct(var3) )
   {
       printf("var3 = |%c| is a punctuation character
", var3 );
   }
   else
   {
       printf("var3 = |%c| is not a punctuation character
", var3 );
   }
   if( ispunct(var4) )
   {
       printf("var4 = |%c| is a punctuation character
", var4 );
   }
   else
   {
       printf("var4 = |%c| is not a punctuation character
", var4 );
   }
   
   return(0);
}

讓我們編譯和執行上面的程式，這將產生以下結果：

var1 = |t| is not a punctuation character
var2 = |1| is not a punctuation character
var3 = |/| is a punctuation character
var4 = | | is not a punctuation character