SQL Not運算子 - tw511教學網

在本教學中，您將學習如何使用SQL NOT運算子來否定SELECT語句WHERE子句中的布林表示式。

在前面已經學習了如何使用各種邏輯運算子，如：AND，OR，LIKE，BETWEEN，IN和EXISTS。這些運算子可幫助您在WHERE子句中形成靈活的條件。

要反轉任何布林表示式的結果，請使用NOT運算子。以下演示如何使用NOT運算子。

NOT [Boolean_expression]

下表顯示了NOT運算子的結果。

原值	應用Not運算子後
TRUE	FALSE
FALSE	TRUE
NULL	NULL

2. SQL NOT運算子範例

我們將使用employees表來演示NOT運算子。employees表的結構如下所示 -

mysql> DESC employees;
+---------------+--------------+------+-----+---------+----------------+
| Field         | Type         | Null | Key | Default | Extra          |
+---------------+--------------+------+-----+---------+----------------+
| employee_id   | int(11)      | NO   | PRI | NULL    | auto_increment |
| first_name    | varchar(20)  | YES  |     | NULL    |                |
| last_name     | varchar(25)  | NO   |     | NULL    |                |
| email         | varchar(100) | NO   |     | NULL    |                |
| phone_number  | varchar(20)  | YES  |     | NULL    |                |
| hire_date     | date         | NO   |     | NULL    |                |
| job_id        | int(11)      | NO   | MUL | NULL    |                |
| salary        | decimal(8,2) | NO   |     | NULL    |                |
| manager_id    | int(11)      | YES  | MUL | NULL    |                |
| department_id | int(11)      | YES  | MUL | NULL    |                |
+---------------+--------------+------+-----+---------+----------------+
10 rows in set

以下語句檢索在部門ID為5中工作的所有員工。如下查詢語句 -

SELECT
    employee_id,
    first_name,
    last_name,
    salary
FROM
    employees
WHERE
    department_id = 5
ORDER BY
    salary;

執行上面範例程式碼，得到以下結果 -

查詢工作在部門ID為5且薪水不超過5000的員工。

SELECT
    employee_id,
    first_name,
    last_name,
    salary
FROM
    employees
WHERE
    department_id = 5
AND NOT salary > 5000
ORDER BY
    salary;

執行上面範例程式碼，得到以下結果 -

+-------------+------------+-----------+--------+
| employee_id | first_name | last_name | salary |
+-------------+------------+-----------+--------+
|         126 | Irene      | Liu       | 2700   |
|         193 | Britney    | Zhao      | 3900   |
|         192 | Sarah      | Yang      | 4000   |
+-------------+------------+-----------+--------+
3 rows in set

SQL NOT IN運算子範例

要否定IN運算子，請使用NOT運算子。例如，以下語句將獲取不在部門ID為1,2或3中工作的所有員工。

SELECT
    employee_id,
    first_name,
    last_name,
    department_id
FROM
    employees
WHERE
    department_id NOT IN (1, 2, 3)
ORDER BY
    first_name;

執行上面查詢語句，得到以下結果 -

+-------------+------------+-----------+---------------+
| employee_id | first_name | last_name | department_id |
+-------------+------------+-----------+---------------+
|         103 | Alexander  | Lee       |             6 |
|         193 | Britney    | Zhao      |             5 |
|         104 | Bruce      | Wong      |             6 |
|         179 | Charles    | Yang      |             8 |
|         109 | Daniel     | Chen      |            10 |
|         105 | David      | Liang     |             6 |
|         107 | Diana      | Chen      |             6 |
|         204 | Hermann    | Wu        |             7 |
|         126 | Irene      | Liu       |             5 |
......
|         100 | Steven     | Lee       |             9 |
|         203 | Susan      | Zhou      |             4 |
|         106 | Valli      | Chen      |             6 |
|         206 | William    | Wu        |            11 |
+-------------+------------+-----------+---------------+
31 rows in set

SQL NOT LIKE運算子範例

可以使用NOT LIKE來否定LIKE運算子。例如，以下語句檢索名字不以字母M開頭的所有員工。

SELECT
    first_name,
    last_name
FROM
    employees
WHERE
    first_name NOT LIKE 'M%'
ORDER BY
    first_name;

執行上面查詢語句，得到以下結果 -

+------------+-----------+
| first_name | last_name |
+------------+-----------+
| Alexander  | Lee       |
| Alexander  | Su        |
| Avg        | Su        |
| Britney    | Zhao      |
| Bruce      | Wong      |
| Charles    | Yang      |
... ...
| Shelley    | Wu        |
| Shelli     | Zhang     |
| Sigal      | Zhang     |
| Steven     | Lee       |
| Susan      | Zhou      |
| Valli      | Chen      |
| William    | Wu        |
+------------+-----------+
34 rows in set

SQL NOT BETWEEN範例

以下範例說明如何使用NOT來否定BETWEEN運算子，以使員工的薪水不在1000到1000之間。

SELECT
    employee_id,
    first_name,
    last_name,
    salary
FROM
    employees
WHERE
    salary NOT BETWEEN 3000
AND 5000
ORDER BY
    salary;

執行上面查詢語句，得到以下結果 -

+-------------+------------+-----------+--------+
| employee_id | first_name | last_name | salary |
+-------------+------------+-----------+--------+
|         119 | Karen      | Zhang     | 2500   |
|         118 | Guy        | Zhang     | 2600   |
|         126 | Irene      | Liu       | 2700   |
|         117 | Sigal      | Zhang     | 2800   |
|         116 | Shelli     | Zhang     | 2900   |
|         104 | Bruce      | Wong      | 6000   |
|         202 | Pat        | Zhou      | 6000   |
|         179 | Charles    | Yang      | 6200   |
... ...
|         205 | Shelley    | Wu        | 12000  |
|         201 | Michael    | Zhou      | 13000  |
|         146 | Karen      | Liu       | 13500  |
|         145 | John       | Liu       | 14000  |
|         102 | Lex        | Liang     | 17000  |
|         101 | Neena      | Wong      | 17000  |
|         100 | Steven     | Lee       | 24000  |
+-------------+------------+-----------+--------+
33 rows in set

SQL NOT EXISTS範例

請參考以下員工和家屬表：

以下查詢使用NOT EXISTS運算子來獲取沒有任何家屬的員工。

SELECT
    employee_id, first_name, last_name
FROM
    employees e
WHERE
    NOT EXISTS (
        SELECT
            employee_id
        FROM
            dependents d
        WHERE
            d.employee_id = e.employee_id
    );

執行上面查詢語句，得到以下結果 -

通過上面的學習，現在您應該知道如何使用NOT運算子來否定布林表示式了。