Java ThreadGroup getMaxPriority()方法

ThreadGroup類的getMaxPriority()方法返回執行緒組的最大優先順序。

語法

public final int getMaxPriority()

返回

此方法返回執行緒組中的執行緒可以具有的最大優先順序

範例

package com.yiibai.threadgroup;

class NewThread extends Thread {
    NewThread(String threadname, ThreadGroup tg) {
        super(tg, threadname);
    }

    public void run() {
        for (int i = 0; i < 10; i++) {
            i++;
        }
        System.out.println(Thread.currentThread().getName() + " completed executing");
    }
}

public class ThreadGroupGetPriorityExp {
    public static void main(String arg[]) throws InterruptedException, SecurityException, Exception {
        // creating a parent threadGroup
        ThreadGroup tg1 = new ThreadGroup("Parent thread");
        // returns the maximum priority of parent thread
        System.out.println("Maximum priority of Parent threadGroup: " + tg1.getMaxPriority());

        // creating a child threadGroup
        ThreadGroup tg2 = new ThreadGroup(tg1, "Child thread");
        // returns the maximum priority of child thread
        System.out.println("Maximum priority of Child threadGroup: " + tg1.getMaxPriority());

        // creating a thread
        NewThread t1 = new NewThread("Thread-1", tg1);
        t1.start();

        // creating another thread
        NewThread t2 = new NewThread("Thread-2", tg2);
        t2.start();
    }
}

執行上面範例程式碼，得到以下結果：

Maximum priority of Parent threadGroup: 10
Maximum priority of Child threadGroup: 10
Thread-1 completed executing
Thread-2 completed executing