java.time.MatchResult.start(int group)
方法返回在此匹配期間由給定組捕獲的子序列的起始索引。
以下是java.time.MatchResult.start(int group)
方法的宣告。
int start(int group)
group
- 此匹配器模式中捕獲組的索引。組捕獲的第一個字元的索引,如果匹配成功但組本身不匹配,則返回-1
。
IllegalStateException
- 如果尚未嘗試匹配,或者上一個匹配操作失敗。IndexOutOfBoundsException
- 如果模式中沒有具有給定索引的捕獲組。以下範例顯示了java.time.MatchResult.start(int group)
方法的用法。
package com.yiibai;
import java.util.regex.MatchResult;
import java.util.regex.Matcher;
import java.util.regex.Pattern;
public class MatchResultDemo {
private static final String REGEX = "(.*)(\\d+)(.*)";
private static final String INPUT = "This is a sample Text, 1234, with numbers in between.";
public static void main(String[] args) {
// create a pattern
Pattern pattern = Pattern.compile(REGEX);
// get a matcher object
Matcher matcher = pattern.matcher(INPUT);
if(matcher.find()) {
//get the MatchResult Object
MatchResult result = matcher.toMatchResult();
//Prints the start index of the subsequence captured by the given group during this match.
System.out.println("Second Capturing Group - Match String start(1): "+result.start(1));
}
}
}
編譯並執行上面的程式,這將產生以下結果 -
Second Capturing Group - Match String start(1): 0