java.time.Matcher.find()方法

java.time.Matcher.find()方法嘗試查詢與模式匹配的輸入序列的下一個子序列。

宣告

以下是java.time.Matcher.find()方法的宣告。

public boolean find()

返回值

當且僅當輸入序列的子序列與此匹配器的模式匹配時才返回true。

範例

以下範例顯示了java.time.Matcher.find()方法的用法。

package com.yiibai;

import java.util.regex.Matcher;
import java.util.regex.Pattern;

public class MatcherDemo {
   private static String REGEX = "(a*b)(foo)";
   private static String INPUT = "aabfooaabfooabfoob";
   private static String REPLACE = "-";

   public static void main(String[] args) {
      Pattern pattern = Pattern.compile(REGEX);

      // get a matcher object
      Matcher matcher = pattern.matcher(INPUT);

      while(matcher.find()) {
         //Prints the offset after the last character matched.
         System.out.println("First Capturing Group, (a*b) Match String end(): "+matcher.end());    
         System.out.println("Second Capturing Group, (foo) Match String end(): "+matcher.end(1));  
      }
   }
}

編譯並執行上面的程式，這將產生以下結果 -

First Capturing Group, (a*b) Match String end(): 6
Second Capturing Group, (foo) Match String end(): 3
First Capturing Group, (a*b) Match String end(): 12
Second Capturing Group, (foo) Match String end(): 9
First Capturing Group, (a*b) Match String end(): 17
Second Capturing Group, (foo) Match String end(): 14