建立一個雙向連結串列,並逆向列印此雙向連結串列中的資料項的範例程式,將以下程式碼儲存到一個原始檔中:display_doubly_linked_list_in_reverse.c, 如下所示 -
#include <stdio.h>
#include <stdlib.h>
struct node {
int data;
struct node *prev;
struct node *next;
};
struct node *head = NULL;
struct node *last = NULL;
struct node *current = NULL;
//display the list
void printList() {
struct node *ptr = head;
printf("\n[head] <=>");
//start from the beginning
while (ptr != NULL) {
printf(" %d <=>", ptr->data);
ptr = ptr->next;
}
printf(" [last]\n");
}
//display the list
void print_backward() {
struct node *ptr = last;
printf("\n[head] <=>");
//start from the beginning
while (ptr != NULL) {
printf(" %d <=>", ptr->data);
ptr = ptr->prev;
}
printf(" [last]\n");
}
//Create Linked List
void insert(int data) {
// Allocate memory for new node;
struct node *link = (struct node*) malloc(sizeof(struct node));
link->data = data;
link->prev = NULL;
link->next = NULL;
// If head is empty, create new list
if (head == NULL) {
head = link;
return;
}
current = head;
// move to the end of the list
while (current->next != NULL)
current = current->next;
// Insert link at the end of the list
current->next = link;
last = link;
link->prev = current;
}
int main() {
insert(10);
insert(20);
insert(30);
insert(40);
insert(50);
insert(60);
printList();
print_backward();
return 0;
}
執行上面程式,得到以下結果 -
[head] <=> 10 <=> 20 <=> 30 <=> 40 <=> 50 <=> 60 <=> [last]
[head] <=> 60 <=> 50 <=> 40 <=> 30 <=> 20 <=> 10 <=> [last]