消磚塊遊戲（EasyX重構進階版）
2020-08-12 18:03:25
如果沒看過這篇文章的朋友可以先去這裏反彈球消磚塊C語言重構函數封裝
因爲這篇是C語言和EasyX結合的版本，也不是很難理解和實現
一個「屏保」
詳細程式碼如下：
#include<conio.h>
#include<graphics.h>
#define high 480
#define width 640
int x, y;
int vx, vy;
int radius;
void startup()
{
x = width / 2;
y = high / 2;
vx = 1;
vy = 1;
radius = 20;
initgraph(width, high);
BeginBatchDraw();
}
void clean()
{
setcolor(BLACK);
setfillcolor(BLACK);
fillcircle(x, y, radius);
}
void show()
{
setcolor(BLUE);
setfillcolor(YELLOW);
fillcircle(x, y, radius);
FlushBatchDraw();
Sleep(3);
}
void updateWithoutInput()
{
x += vx;
y += vy;
if(x <= radius || x >= width - radius)
vx = -vx;
if(y <= radius || y >= high - radius)
vy = -vy;
}
void updateWithInput()
{
}
void gameover()
{
EndBatchDraw();
closegraph();
}
int main()
{
startup();
while(1)
{
clean();
updateWithoutInput();
updateWithInput();
show();
}
gameover();
return 0;
}
新增一塊擋板
效果演示如下：
詳細程式碼如下：
#include<conio.h>
#include<graphics.h>
#define high 480
#define width 640
int x, y; //小球's situation
int vx, vy;
int radius;
int x2, y2; //擋板's central situation
int high2, width2;
int left, right, top, bottom;
void startup()
{
x = width / 2;
y = high / 2;
vx = 1;
vy = 1;
radius = 20;
high2 = high / 20;
width2 = width / 5;
x2 = width / 2;
y2 = high - high2 / 2;
left = x2 - width2 / 2;
right = x2 + width2 / 2;
top = y2 - high2 / 2;
bottom = y2 + high2 / 2;
initgraph(width, high);
BeginBatchDraw();
}
void clean() //擦除的效果
{
setcolor(BLACK);
setfillcolor(BLACK);
fillcircle(x, y, radius);
bar(left, top, right, bottom);
}
void show()
{
setcolor(BLUE);
setfillcolor(YELLOW);
fillcircle(x, y, radius);
setfillcolor(BROWN);
bar(left, top, right, bottom);
FlushBatchDraw();
Sleep(3);
}
void updateWithoutInput()
{
x += vx;
y += vy;
if(x <= radius || x >= width - radius)
vx = -vx;
if(y <= radius || y >= high - radius)
vy = -vy;
}
void updateWithInput()
{
}
void gameover()
{
EndBatchDraw();
closegraph();
}
int main()
{
startup();
while(1)
{
clean();
updateWithoutInput();
updateWithInput();
show();
}
gameover();
return 0;
}
控制擋板接球
效果演示如下：
這一塊只是完善了使用者輸入部分的函數
詳細程式碼：
#include<conio.h>
#include<graphics.h>
#define high 480
#define width 640
int x, y; //小球's situation
int vx, vy;
int radius;
int x2, y2; //擋板's central situation
int high2, width2;
int left, right, top, bottom;
void startup()
{
x = width / 2;
y = high / 2;
vx = 1;
vy = 1;
radius = 20;
high2 = high / 20;
width2 = width / 5;
x2 = width / 2;
y2 = high - high2 / 2;
left = x2 - width2 / 2;
right = x2 + width2 / 2;
top = y2 - high2 / 2;
bottom = y2 + high2 / 2;
initgraph(width, high);
BeginBatchDraw();
}
void clean() //擦除的效果
{
setcolor(BLACK);
setfillcolor(BLACK);
fillcircle(x, y, radius);
bar(left, top, right, bottom);
}
void show()
{
setcolor(BLUE);
setfillcolor(YELLOW);
fillcircle(x, y, radius);
setcolor(BLUE);
setfillcolor(BROWN);
bar(left, top, right, bottom);
FlushBatchDraw();
Sleep(3);
}
void updateWithoutInput()
{ //考慮到球位於擋板上或擋板下的情況
if(((y + radius >= top) && (y + radius < bottom - high2 / 3)) || (( y - radius <= bottom) && (y - radius > top - high2 / 3)))
if((x >= left) && (x <= right))
vy = -vy;
x += vx;
y += vy;
if(x <= radius || x >= width - radius)
vx = -vx;
if(y <= radius || y >= high - radius)
vy = -vy;
}
void updateWithInput()
{
char input;
if(kbhit())
{
input = getch();
if(input == 'a' && left > 0)
{
x2 -= 15;
left = x2 - width2 / 2;
right = x2 + width2 / 2;
}
if(input == 'd' && right < width)
{
x2 += 15;
left = x2 - width2 / 2;
right = x2 + width2 / 2;
}
if(input == 'w' && top > 0)
{
y2 -= 15;
top = y2 - high2 / 2;
bottom = y2 + high2 / 2;
}
if(input == 's' && bottom < high)
{
y2 += 15;
top = y2 - high2 / 2;
bottom = y2 + high2 / 2;
}
}
}
void gameover()
{
EndBatchDraw();
closegraph();
}
int main()
{
startup();
while(1)
{
clean();
updateWithoutInput();
updateWithInput();
show();
}
gameover();
return 0;
}
終極版消磚塊（難度：簡易）
詳細程式碼如下：
#include<conio.h>
#include<graphics.h>
#define high 480
#define width 640
#define num 10
int x, y; //小球's situation
int vx, vy;
int radius;
int x2, y2; //擋板's central situation
int high2, width2; //擋板高寬
int left, right, top, bottom;
int exist[num]; //記錄磚塊是否exist,1表exist,0表消失
int high3, width3; //每個磚塊的高寬
void startup()
{
x = width / 2;
y = high / 2;
vx = 1;
vy = 1;
radius = 20;
high2 = high / 20;
width2 = width / 3;
x2 = width / 2;
y2 = high - high2 / 2;
left = x2 - width2 / 2;
right = x2 + width2 / 2;
top = y2 - high2 / 2;
bottom = y2 + high2 / 2;
width3 = width / num; //磚塊寬高
high3 = high / (num + 2);
int i;
for(i = 0; i < num; i++)
exist[i] = 1; //磚塊exist Array初始化
initgraph(width, high);
BeginBatchDraw();
}
void clean() //擦除的效果
{
setcolor(BLACK);
setfillcolor(BLACK);
fillcircle(x, y, radius);
bar(left, top, right, bottom);
int i, left3, right3, top3, bottom3;
for(i = 0; i < num; i++)
{
left3 = i * width3;
right3 = left3 + width3;
top3 = 0;
bottom3 = high3;
if(!exist[i]) //磚塊被消了
fillrectangle(left3, top3, right3, bottom3);
}
}
void show()
{
setcolor(BLUE);
setfillcolor(YELLOW);
fillcircle(x, y, radius);
setcolor(BLUE);
setfillcolor(BROWN);
bar(left, top, right, bottom);
int i, left3, right3, top3, bottom3;
for(i = 0; i < num; i++)
{
left3 = i * width3;
right3 = left3 + width3;
top3 = 0;
bottom3 = high3;
if(exist[i])
{
setcolor(WHITE);
setfillcolor(CYAN);
fillrectangle(left3, top3, right3, bottom3);
}
}
FlushBatchDraw();
Sleep(1);
}
void updateWithoutInput()
{ //考慮到球位於擋板上或擋板下的情況
if(((y + radius >= top) && (y + radius < bottom - high2 / 2)) || (( y - radius <= bottom) && (y - radius > top - high2 / 2)))
if((x >= left) && (x <= right))
vy = -vy;
x += vx;
y += vy;
if(x <= radius || x >= width - radius)
vx = -vx;
if(y <= radius || y >= high - radius)
vy = -vy;
int i, left3, right3, top3, bottom3;
for(i = 0; i < num; i++)
{
if(exist[i])
{
left3 = i * width3;
right3 = left3 + width3;
bottom3 = high3;
if((y == bottom3 + radius) && (x >= left3) && (x <= right3))
{
exist[i] = 0;
y += 1;
vy = -vy;
}
}
}
}
void updateWithInput()
{
char input;
if(kbhit())
{
input = getch();
if(input == 'a' && left > 0)
{
x2 -= 15;
left = x2 - width2 / 2;
right = x2 + width2 / 2;
}
if(input == 'd' && right < width)
{
x2 += 15;
left = x2 - width2 / 2;
right = x2 + width2 / 2;
}
if(input == 'w' && top > 0)
{
y2 -= 15;
top = y2 - high2 / 2;
bottom = y2 + high2 / 2;
}
if(input == 's' && bottom < high)
{
y2 += 15;
top = y2 - high2 / 2;
bottom = y2 + high2 / 2;
}
}
}
void gameover()
{
EndBatchDraw();
closegraph();
}
int main()
{
startup();
while(1)
{
clean();
updateWithoutInput();
updateWithInput();
show();
}
gameover();
return 0;
}