1.遞迴函數的引數和返回值
2.遞迴出口
3.單層遞迴的邏輯
給你二元樹的根節點 root ,返回它節點值的 前序 遍歷。
/**
* Definition for a binary tree node.
* public class TreeNode {
* int val;
* TreeNode left;
* TreeNode right;
* TreeNode() {}
* TreeNode(int val) { this.val = val; }
* TreeNode(int val, TreeNode left, TreeNode right) {
* this.val = val;
* this.left = left;
* this.right = right;
* }
* }
*/
class Solution {
public List<Integer> preorderTraversal(TreeNode root) {
List<Integer> result = new ArrayList<>();
preoder(root,result);
return result;
}
public void preoder(TreeNode node,List<Integer> result){
if (node==null){
return;
}
result.add(node.val);//前序遍歷:中、左、右
preoder(node.left,result);
preoder(node.right,result);
}
}
給定一個二元樹的根節點 root ,返回 它的 中序 遍歷 。
/**
* Definition for a binary tree node.
* public class TreeNode {
* int val;
* TreeNode left;
* TreeNode right;
* TreeNode() {}
* TreeNode(int val) { this.val = val; }
* TreeNode(int val, TreeNode left, TreeNode right) {
* this.val = val;
* this.left = left;
* this.right = right;
* }
* }
*/
class Solution {
public List<Integer> inorderTraversal(TreeNode root) {
List<Integer> result = new ArrayList();
inorder(root,result);
return result;
}
public void inorder(TreeNode node, List<Integer> result){
if(node==null){
return;
}
inorder(node.left,result);//中序遍歷:左、中、右
result.add(node.val);
inorder(node.right,result);
}
}
給你一棵二元樹的根節點 root ,返回其節點值的 後序遍歷 。
/**
* Definition for a binary tree node.
* public class TreeNode {
* int val;
* TreeNode left;
* TreeNode right;
* TreeNode() {}
* TreeNode(int val) { this.val = val; }
* TreeNode(int val, TreeNode left, TreeNode right) {
* this.val = val;
* this.left = left;
* this.right = right;
* }
* }
*/
class Solution {
public List<Integer> postorderTraversal(TreeNode root) {
List<Integer> result = new ArrayList();
postorder(root,result);
return result;
}
public void postorder(TreeNode node,List<Integer> result){
if(node==null){
return;
}
postorder(node.left,result);//後序遍歷:左、右、中
postorder(node.right,result);
result.add(node.val);
}
}
用棧操作,遞迴也是用棧實現的嘛